2x + 7 ≤ 3x - 5
Isolate the x. Subtract 3x and 7 from both sides
2x (-3x) + 7 (-7) ≤ 3x (-3x) - 5 (-7)
2x - 3x ≤ -5 - 7
Combine like terms
(2x - 3x) ≤ (-5 - 7)
-x ≤ -12
Isolate the x. Divide -1 from both sides. Remember that when dividing by a negative number, you must flip the sign.
(-x)/-1 ≤ (-12)/-1
x ≥ -12/-1
x ≥ 12
x ≥ 12 is your answer
~Rise Above the Ordinary