Question

What is the remainder when the polynomial 8 x^2 +4x−3 is divided by 2x−1 ?

Answer 1

The remainder is one.. a quick way to do this is by finding what value of 2x-1=0 then sub that into the original equation. In this case sub x=1/2 into 8x^2 + 4x-3 ... this will give you the remainder

Answer 2

`8x^2 +4x-3` is divided by 2x-1

We use long division

4x +4 ------------> Quotient

----------------------------

2x-1 8x^2 +4x−3

8x^2 - 4x (Subtract it from the top)

---------------------------

+ 8x -3

8x - 4 (Subtract it from the top)

----------------------------------

+1 ------------> Remainder

So , 1 is the remainder.