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5 votes
Simplify the fraction and state the excluded value(s).


(7x^2+4x-20)/(5x+10)

2 Answers

3 votes


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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  8. Left to Right
  9. Algebra I

Terms/Coefficients

Factoring

Calculus

Discontinuities

  • Removable (Holes)
  • Jump (Piece-wise functions)
  • Infinite (Asymptotes)

^_^ ❤

User Justqb
by
6.4k points
6 votes

Answer:


\displaystyle (7x^2 + 4x - 20)/(5x + 10) = (7x - 10)/(5), x \\eq -2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Terms/Coefficients
  • Factoring

Calculus

Discontinuities

  • Removable (Holes)
  • Jump (Piece-wise functions)
  • Infinite (Asymptotes)

Explanation:

Step 1: Define


\displaystyle (7x^2 + 4x - 20)/(5x + 10)

Step 2: Simplify

  1. [Frac - Numerator] Factor quadratic:
    \displaystyle ((7x - 10)(x + 2))/(5x + 10)
  2. [Frac - Denominator] Factor GCF:
    \displaystyle ((7x - 10)(x + 2))/(5(x + 2))
  3. [Frac] Divide/Simplify:
    \displaystyle ((7x - 10))/(5), x \\eq -2

When we divide (x + 2), we would have a removable discontinuity. If we were to graph the original function, we would see at x = -2 there would be a hole in the graph.

User Flimm
by
6.1k points