Question

the fastest airplane is the lockheed sr 71 blackbird a high altitude spy plane first built in 1964. if an sr-71 is clocked traveling 15.0 km west in 15.3 s, what is its average velocity in kilometers per hours

Answer 1

For the motion of the plane it is given to us that it travel 15.0 km in 15.3 s

So here we can use the formula of average velocity to find it

formula is given as ratio of total displacement and total time

`v = (displacement)/(time)`

here it is given that

`displacement = 15.0 km`

time = 15.3 s

we need to convert the time into hour as the speed is required in km/h

so we know that

`1 h = 3600 s`

`t = 15.3 s * (1h)/(3600 s)`

`t = 4.25 * 10^(-3) h`

now by the above formula

`v = (15.0)/(4.25 * 10^(-3))`

`v = 3529.4 km/h`

so the velocity of the plane would be 3529.4 km/h