Question

the room shown below right is 14ft by 10ft. Find the dimensions of each piece of furniture to the nearest tenth.

Answer 1

The dimension of dresser is :

Length is 6.0 feet

width is 3.0 feet

The dimension of bed is :

Length is
`5√(2)` = 7.1 feet

Width is
`4√(2)` = 5.7 feet

The dimension of table:

Length is
`2√(2)` = 2.8 feet

Width is
`2√(2)` = 2.8 feet

Answer 2

A). Dimensions of the bed = 7.1 ft × 5.7 ft

B). Dimensions of table = 2.8 ft × 2.8 ft

C). Dimensions of the dresser = 6ft × 3ft

Explanation:

Dimensions of the room are 14 ft by 10 ft.

We have to find the dimensions of each furniture.

First we take the bed.

Length of the bed =
`\sqrt{(5)^(2)+(5)^(2)}`

=
`√(25+25)`

=
`√(50)`

= 7.07 ft ≈ 7.1 ft

Width of the bed =
`\sqrt{4^(2)+4^(2)}`

=
`√(16+16)`

=
`√(32)`

= 5.7 ft

We take another furniture table which is in the square shape,

Side of the table =
`\sqrt{2^(2)+2^(2)}`

=
`√(8)`

= 2.8 ft

Therefore, each side of the table is 2.8 ft

Length of the dresser = 6 ft

Width of the dresser = 3 ft