How does sec(x)-1/tan(x) + tan(x)/sec(x)+1 = 2sin(x)/1+cos(x)

asked Feb 20, 2019 149k views

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Answer in the attachment.

Used:

$\sec x=(1)/(\cos x)\\\\\tan x=(\sin x)/(\cos x)\\\\\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x$

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