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What is the molarity of a 250.0 ml aqueous solution of sodium hydroxide that contains 15.5 grams of solute?

User Aring
by
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2 Answers

4 votes

Answer:

Molarity of solution is 1.5501

Step-by-step explanation:

Given data:

Molarity of NaOH = ?

Volume of solution = 250 ml

Mass of solute = 15.5 grams

Solution:

Formula:

Molarity = Mass of solute/Molar mass of solute * 1/volume of solution in liters.

First convert volume into Liters = 250/1000 =0.25 L

Now put the values in formula:

Molarity of NaOH = 15.5/39.997 * 1/0.25

= 1.5501

Molarity of NaOH = 1.55011


User Josh Gust
by
7.9k points
3 votes

The molar concentration of the solution is 1.55 mol/L.


1. Convert grams to moles.



\text{Moles of NaOH} = 15.5 \text{g NaOH} * \frac{\text{1 mol NaOH}}{\text{40.00 g NaOH}} = \text{0.3875 mol NaOH}\\

2. Convert millilitres to litres



V = 250.0 \text{mL} * \frac{\text{1 L}}{\text{1000 mL}} = \text{0.2500 L}\\

3. Calculate the molar concentration (c)



c = \frac{\text{moles}}{\text{litres}} = \frac{\text{0.2875 mol}}{\text{0.2500 L}} = \textbf{1.55 mol/L}



User Chuim
by
8.6k points