Question

If(x)=x/2-3 and g(x)=4x2+x-4 find (f+g)(x)

Answer 1

`(f+g)(x)=4x^2+(3)/(2)x-7`

Answer 2

`h(x)=4x^2+(3)/(2)x-7`

Explanation:

Given:

`f(x)=(x)/(2)-3`

`g(x)=4x^2+x-4`

To find: (f+g)(x)

It is a composite function. Sum of f and g function.

`h(x)=f(x)+g(x)`

`h(x)=(x)/(2)-3+4x^2+x-4`

Combine the like term

`h(x)=4x^2+(3)/(2)x-7`

Hence, The sum of f(x) and g(x) would be
`h(x)=4x^2+(3)/(2)x-7`