A rock fell from a cliff at 108 feet high and landed on an embankment feet from the ground. find the amount if time it would have taken the rock to fall.

Question

asked Jan 21, 2019 184k views

1 Answer

Eenoku · Answer 1 · 2019-01-26T03:39:18+0000

To solve this problem we will directly use the formula:

h=(1)/(2)gt^2 ..........Equation 1

where symbols have their usual meanings.

Here g=32.2 ft/s^2 and h=108 feet

Therefore, from Equation 1 we will get:

$t=\sqrt{(2h)/(g)}$ ....Equation 2

Plugging in the values in Equation 2 we get:

$t=\sqrt{(2* 108)/(32.2)}\approx 2.59$ seconds.

Therefore, the amount of time it would have taken the rock to fall is 2.59 seconds.