X= -10
9/2(8-x)+36=102-5/2(3x+24)
We move all terms to the left:
9/2(8-x)+36-(102-5/2(3x+24))=0
Domain of the equation: 2(8-x)!=0
x∈R
Domain of the equation: 2(3x+24))!=0
x∈R
We add all the numbers together, and all the variables
9/2(-1x+8)-(102-5/2(3x+24))+36=0
We calculate fractions
(18x3/(2(-1x+8)*2(3x+24)))+(-(-10x0)/(2(-1x+8)*2(3x+24)))+36=0
We calculate terms in parentheses: +(18x3/(2(-1x+8)*2(3x+24))), so:
18x3/(2(-1x+8)*2(3x+24))
We multiply all the terms by the denominator
18x3
We add all the numbers together, and all the variables
18x^3