Calculate the midpoint of a line segment with the endpoints 7,12 and -1,6

asked Dec 13, 2019 111k views

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The formula of a midpoint:

$M_(AB)\left((x_A+x_B)/(2),\ (y_A+y_B)/(2)\right)$

We have:

$A(7,\ 12)\to x_A=7,\ y_A=12\\B(-1,\ 6)\to x_B=-1,\ y_B=6$

Substitute:

$(7+(-1))/(2)=(7-1)/(2)=(6)/(2)=3\\\\(12+6)/(2)=(18)/(2)=9$

Hu Qiang answered Dec 17, 2019

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