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Write an equation for a line perpendicular to y = 3x + 2 and passing through the point (9,1)

User Michael Entin
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1 Answer

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13 votes

Explanation:

the slope of a line is always the factor of x, and it is defined as ratio (y coordinate change / x coordinate change) when going from one point to another on the line.

in that sense it is y/x.

the perpendicular slope turns that ratio upside-down and flips the overall sign.

so, in our case, the original slope is 3 = 3/1.

the perpendicular slope is then -1/3.

so, now, we have the slope and a point, and we can start with the point-slope form of the line equation :

y - y1 = a(x - x1)

"a" being the slope, (x1, y1) being the point.

y - 1 = -1/3 × (x - 9) = -x/3 + 3

y = -x/3 + 4

and that is the usual slope-intercept form

y = ax + b

"a" is again the slope, "b" is the y-intercept (the y value when x = 0).

User Britter
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