Question

How many grams of water are produced when 37.7 g of hydrogen peroxide (H2O2) decomposes into oxygen gas and water?

Answer 1

Mass of water produced = 19.8 g

Step-by-step explanation:

Given data:

Mass of hydrogen peroxide = 37.7 g

Mass of water produced = ?

Solution:

Chemical equation:

2H₂O₂ → 2H₂O + O₂

Number of moles of H₂O₂:

Number of moles = mass/molar mass

Number of moles = 37.7 g/ 34 g/mol

Number of moles = 1.1 mol

Now we will compare the moles of H₂O₂ and H₂O from balance chemical equation in order to determine the moles of water formed.

H₂O₂ ; H₂O

2 : 2

1.1 : 1.1

Mass of water formed:

Mass = number of moles × molar mass

Mass = 1.1 mol × 18 g/mol

Mass = 19.8 g