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Solve for y

{2x}^(2) - {y}^(2) = 8

User Mcsilvio
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1 Answer

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-y^2 = -2x^2 + 8

y^2 = 2x^2 - 8

y =

\sqrt{2 {x}^(2 ) - 8 }



User Debadatt
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