Question

A standard solution is prepared for the analysis of fluoxymesterone (c20h29fo3; 336 g/mol), an anabolic steroid. a stock solution is first prepared by dissolving 16.8 mg of fluoxymesterone in enough water to give a total volume of 500.0 ml. a 1.0 μl aliquot (portion) of this stock solution is taken out and then diluted to a final volume of 1.0 ml. calculate the final concentration of this new solution in m.

Answer 1

• The concentration of new solution will be 1×10∧-7 M.

Solution:

Data Given

given mass of fluoxymesterone =16.8mg = 0.0168 g

molar mass of fluoxymesterone = 336g/mol

vol. of fluoxymesterone = 500.0 ml = 0.500 L

Stock Molarity of fluoxymesterone = (0.0168/336)÷0.500 = 1×10∧-4 M

So applying dilution formula

Stock Solution : New Solution

M1.V1 = M2.V2

( 1×10∧-4 M) × (1×10∧-6 L) = M2 × 0.001 L

[( 1×10∧-4) × (1×10∧-6)]÷[0.001] = M2

1 × 10∧-7 = M2

Result:

• The concentration of new solution M2 will be 1 × 10∧-7