Question

In a lab, a substance was cooked by 42 C over a period of 7 hours at a constant rate. What was the change in temperature each hour

Answer 1

Given that we have the change in temperature over 7 hours and we are looking for the change over 1 hour, we can divide the total change in temperature by 7. Thus, the change in temperature would be
`(42)/(7) C^(\circ)`.

Additionally, this can be solved by equations:

`\frac{42 \,\textrm{C}^(\circ)}{7 \,\textrm{hours}} = \frac{x \,\textrm{C}^(\circ)}{1 \,\textrm{hour}}`

`1 \,\textrm{hour} \cdot \frac{42 \,\textrm{C}^(\circ)}{7 \,\textrm{hours}} = x \,\textrm{C}^(\circ)`

`(42)/(7) \,\textrm{C}^(\circ) = x \,\textrm{C}^(\circ)`

`(42)/(7) = x`

By using two different methods, we can determine that the change each hour was equal to 42/7 C° per hour.