Question

Someone please help I don’t understand this

Answer 1

to get the equation of any straight line, we simply need two points off of it, again, let's use the ones from the table in the picture below.

`(\stackrel{x_1}{2}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{11}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{11}-\stackrel{y1}{7}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{2}}} \implies \cfrac{ 4 }{ 2 }\implies 2`

`\begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{2}(x-\stackrel{x_1}{2}) \\\\\\ y-7=2x-4\implies {\LARGE \begin{array}{llll} y=2x+3 \end{array}}`