we are given
![f(x)=(1)/(x)](https://img.qammunity.org/2019/formulas/mathematics/college/kdlcyqpq4wr9xi1mup1qzio5jpywpyp12s.png)
![g(x)=√(x+5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ifaoa7pask9y2heeyi1eqwqaxhqru4oy86.png)
Calculation of (f/g)(x):
![((f)/(g))(x)=(f(x))/(g(x))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9fsuk6x8km4pdx45qmvg9oqs0rcdwr5sx2.png)
now, we can plug values
![((f)/(g))(x)=((1)/(x))/(√(x+5))](https://img.qammunity.org/2019/formulas/mathematics/high-school/hjon3ajgj3oogr2877gh68aj3vcdkjmkz4.png)
now, we can simplify it
![((f)/(g))(x)=(1)/(x√(x+5))](https://img.qammunity.org/2019/formulas/mathematics/high-school/2xa8y0sf3vohmnmaf48744jnsstsfn9gul.png)
Domain:
we know that domain is all possible values of x for which any function is defined
function will be undefined when denominator =0
![x√(x+5) =0](https://img.qammunity.org/2019/formulas/mathematics/high-school/pmjnddwshzbyxd4nh8jr6pfofck3jeo3m4.png)
![x=-5,x=0](https://img.qammunity.org/2019/formulas/mathematics/high-school/yebi455iqk0sxxhdjilxprnqo5gbcuakw5.png)
we are given sqrt function
and we know that value inside sqrt will always be greater than 0
![x+5>0](https://img.qammunity.org/2019/formulas/mathematics/high-school/jl72bex06ilmu1y5fcs8besfx9wf6dy9qh.png)
![x>-5](https://img.qammunity.org/2019/formulas/mathematics/high-school/d8gphzg3zj8yn1z9jpsoew9tjdn0mse8qv.png)
so, domain will be
..............Answer