Question

How many moles of NaCl are created as a result of decomposing 12 grams of NaClO3? (molar mass of Na=23, Cl=35, O=16)

Answer 1

Answer: 0.113 moles of NaCl are created as a result of decomposing 12 grams of
`NaClO_3`.

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} NaClO_3=(12g)/(106.5g/mol)=0.113moles`

The balanced chemical equation for decomposition of
`NaClO_3` is:

`2NaClO_3\rightarrow 2NaCl+3O_2`

According to stoichiometry :

2 moles of
`NaClO_3` give = 2 moles of
`NaCl`

Thus 0.113 moles of
`NaClO_3` give =
`(2)/(2)* 0.113=0.113moles` of
`NaCl`

Thus 0.113 moles of NaCl are created as a result of decomposing 12 grams of
`NaClO_3`.