Question

In tossing four fair dice, what is the probability of tossing, at most, one 3

Answer 1

In tossing four fair dice, the probability of getting at most one 3 is 0.86.

Solution-

The probability of getting at most one 3 is, either getting zero 3 or only one 3.

`P(A) =The \ probability \ of \ getting \ zero \ 3 =((5)/(6))((5)/(6))((5)/(6))((5)/(6))=(625)/(1296) =0.48` ( ∵ xxxx )

`P(B) = The \ probability \ of \ getting \ only \ one \ 3 =(4)((1)/(6))((5)/(6))((5)/(6))((5)/(6)) = 0.38` ( ∵ 3xxx, x3xx, xx3x, xxx3 )

P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86