1 Answer

Remo · Answer 1 · 2019-07-10T10:46:53+0000

9.

4 < 5 < 9

2^2 < 5 < 3^2

$2 < \sqrt 5 < 3$

$-3 < -\sqrt 5 < -2 < -1.96312...$

$-\sqrt 5 < -1.96312...$

10.

The least will be one of the negative ones, -3 or -6/5. Since -6/5=-1.2, we see

-3 is the least

11.

81 < 90 < 100

9^2 < 90 < 10^2

9 < √(90) < 10

Answer: 10 feet

12.

We know
$\sqrt 8 > \sqrt 5$ and
$2.5 > 2 \frac 1 3$

Since

2.5^2 = 6.25 < 8

$\sqrt 8$ is the tallest.

Please log in or register to add a comment.