Question

A jogger runs 10.0 blocks do east, 5.0 blocks due South, and another two. Zero blocks do east. Assume all blocks are equal size, what is the magnitude of the joggers net displacement?

Answer 1

13 blocks

Step-by-step explanation:

Answer 2

Jogger moves in three displacements

d1 = 10 blocks East

d2 = 5 blocks South

d3 = 2 blocks East

now we can say

total displacement towards East direction will be

`d_x = 10 + 2= 12 blocks`

Total displacement towards South

`d_y = 5 block`

now to find the net displacement we can use vector addition

`d = √(d_x^2 + d_y^2)`

`d = √(12^2 + 5^2)`

`d = 13 blocks`

so magnitude of net displacement will be equal to 13 blocks