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1 vote
What substitution should be used to rewrite 16(x^3+1)^2-22(x^3+1)-3=0 as a quadratic equation?

2 Answers

2 votes


16(x^3+1)^2-22(x^3+1)-3=0\\\\\text{substitute}\ t=x^3+1\\\\16t^2-22t-3=0

User SimonBarker
by
5.3k points
6 votes

Answer:B on edge

Explanation:

User Eric Green
by
5.5k points
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