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P− 1/4 = 3/8 + 1/2 p

User Travega
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p-(1)/(4)=(3)/(8)+(1)/(2)p\ \ \ \ |\cdot8\\\\8p-\\ot8^2\cdot(1)/(\\ot4_1)=\\ot8^1\cdot(3)/(\\ot8_1)+\\ot8^4\cdot(1)/(\\ot2_1)p\\\\8p-2=3+4p\ \ \ \ |+2\\\\8p=5+4p\ \ \ \ |-4p\\\\4p=5\ \ \ \ |:4\\\\\boxed{p=(5)/(4)}

User Jihoon Kim
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