Question

Determine the distance finding the exact value in simplest form and aproximate to the 1 decimal place (3,-3) and (-3,5)

Answer 1

We are given coordinates : (3,-3) and (-3,5).

In order to find the distance between two coordinates, we use distance formula.

Distance between two points(d) =
`√((x_2-x_1)^2-(y_2-y_1)^2)`

Plugging values of x1, y1, x2 and y2 in above formula.

Distnace=
`√((-3-3)^2+(5-(-3))^2)`

=
`√((-6)^2+(5+3)^2)`

=
`√(36+64)`

=
`√(100)`

Square root of 100 is 10.

Therefore,
`√(100)=10`

The exact value of distance between (3,-3) and (-3,5) is 10.0 .