Question

I NEED HELP!!! This is due tonight and I need help solving

Answer 1

x = 2
`√(5)`

Explanation:

Okay first you need to find the side of the other triangle (the side that also is a hypotenuse for the other triangle).

So we can use pythagorean's theorum

`a^(2) +b^(2) =c^(2)` with c being the hypotenuse

`a^(2) +2^(2) =7^(2)`

a^2 + 4 = 49 subtract 4 from both sides

a^2 = 45 then do the sqaure root

a =
`√(45)` which can be simplified to 3
`√(5)`

so... 3
`√(5)` or
`√(45)` is our hypotenuse for the other triangle

`5^(2) +b^(2) = √(45) ^(2)`

25 + b^2 = 45 subtract 25 from both sides

b^2 = 20 then do the square root

b (or x in this problem) =
`√(20)`

or when simplified, 2
`√(5)`