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The sum of two numbers is 36. Twice the first number minus the second is 6. Find the numbers

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x,\ y-the\ numbers\\\\\underline{+\left\{\begin{array}{ccc}x+y=36\\2x-y=6\end{array}\right}\ \ \ \ |add\ both\ sides\ of\ equations\\.\ \ \ \ \ 3x=42\ \ \ \ |:3\\.\ \ \ \ \ \ x=14\\\\\text{put the value of x to the first equation}\\\\14+y=36\ \ \ \ |-14\\y=22\\\\Answer:\ 14\ and\ 22

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