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Solve for y, y(a-b)=c(y+a)

User AShah
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y(a-b)=c(y+a)\ \ \ \ |\text{use distributive property}\\\\ya-yb=cy+ca\ \ \ \ |-cy\\\\ya-yb-yc=ca\\\\y(a-b-c)=ca\ \ \ \ |:(a-b-c)\\eq0\\\\\boxed{y=(ca)/(a-b-c)}