Answer:
C) 8000 at 6%; 2000 at 11%
Explanation:
Let x represent the amount invested at 11%. Then the total interest earned is ...
0.11x +0.06(10000 -x) = 700
0.05x = 100 . . . . . . . . . subtract 600, collect terms
x = 2000 . . . . . . . . . divide by 0.05
8000 is invested at 6%; 2000 is invested at 11%.