Question

How many grams of h2 are needed to produce 14.51 g of nh3?

Answer 1

2.57 g of H₂

Solution:

The Balance Chemical Equation is as follow,

N₂ + 3 H₂ → 2 NH₃

According to Balance equation,

34.06 g (2 moles) NH₃ is produced by = 6.04 g (3 moles) of H₂

So,

14.51 g of NH₃ will be produced by = X g of H₂

Solving for X,

X = (14.51 g × 6.04 g) ÷ 34.06 g

X = 2.57 g of H₂