While returning back in opposite direction driver see that rain drops are falling vertically down
so horizontal speed of rain with respect to driver must be Zero
while moving towards the north direction driver see that the rain drops makes an angle 38 degree with the vertical
![tan\theta = (v_y)/(v_x)](https://img.qammunity.org/2019/formulas/physics/high-school/iyp9606mefrhrhudgp4xvrrfl9jf5cfmml.png)
![tan38 = (v_y)/(25 + 25)](https://img.qammunity.org/2019/formulas/physics/high-school/3r24veqb5e0vfw2bc34cgprqhljmo7blxu.png)
![v_y = 39 m/s](https://img.qammunity.org/2019/formulas/physics/high-school/d6cd5r2hpgfbdofyt6b9ehvnbvix5r8tme.png)
so the speed of rain is
![v = √(25^2 + 39^2)](https://img.qammunity.org/2019/formulas/physics/high-school/8zz2vvolid5ggh2ufxtaxzcwxqb4ljxom2.png)
![v = 46.3 m/s](https://img.qammunity.org/2019/formulas/physics/high-school/z36rw4cnqd0zgwcwmq2zkwpa4njbwo1k9g.png)
also the angle is given as
![\theta = tan^(-1)(39)/(25)](https://img.qammunity.org/2019/formulas/physics/high-school/n031gdjf0c9s5kswu43go1dq44u3fu3ecn.png)
![\theta = 57.3 degree](https://img.qammunity.org/2019/formulas/physics/high-school/2yenomqw7t7nkl5sxjm31o48kcah6re3qs.png)