Question

An experiment is performed in which the molar mass of a gas is found to be 48.45 gmol-1. The published (actual) value is 52.98 g mol. Calculate the percentage error.

Answer 1

Answer: The percentage error is 8.55 %.

Step-by-step explanation:

To calculate the percentage error, we use the equation:

`\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}* 100`

We are given:

Experimental value of molar mass = 48.45 g/mole

Accepted value of molar mass = 52.98 g/mole

Putting values in above equation, we get:

`\%\text{ error}=(|48.45-52.98|)/(52.98)* 100\\\\\%\text{ error}=8.55\%`

Hence, the percentage error is 8.55 %.

Answer 2

Experimental molar mass = 48.45 g/mol. Actual molar mass = 52.98 g/mol. Error in molar mass= (52.98-48.45) = 4.53. Percentage error in molar mass= (Error in molar mass)/Actual molar mass = (4.53/52.98)X100= 8.55 %. The formula utilised here is percentage error= (Exact value - Approximate value)X100/Exact value. First approximate value is to be subtracted from exact value, then divide the number by exact value. Finally, the fraction is to be multiplied by 100 to get percentage error.