The chemical equation for the combustion of propane can be represented as,
![C_(3)H_(8)(g) + 5O_(2)(g)-->3CO_(2)(g) + 4H_(2)O(g)](https://img.qammunity.org/2019/formulas/chemistry/high-school/xh2odu5eresdjukw5lp47529iuanvgavm7.png)
1 mol propane requires 5 mol oxygen for complete reaction to produce 3 mol carbon dioxide and 4 mol water.
Mass of propane = 25.0 g
Mass of oxygen = 90.7 g
The total mass of reactants = 25.0 g + 90.7 g = 115.7 g
According to Law of conservation of mass, the total mass of reactants will be equal to the total mass of products formed in a chemical reaction.
Therefore, here the mass of water and carbon dioxide will be 115.7 g
Correct answer: a. 115.7 g