Question

D(-3+x)=kx+9 solve for x

Answer 1

d(-3 + x) = kx + 9

• Distribute d inside the parentheses.

-3d + dx = kx + 9

• Subtract kx from both sides.

-3d + dx - kx = 9

• Add 3d to both sides.

dx - kx = 9 + 3d

• Factor x out of dx - kx.

x(d - k) = 9 + 3d

• Divide both sides by d - k.

x =
`(9+3d)/(d-k)`

• If you want to simplify this even more, factor 3 out of the numerator.

x =
`(3(d + 3))/(d-k)`