Question

Determining the Axis of Symmetry of Quadratic Functions Which functions have an axis of symmetry of x = –2? Check all that apply. f(x) = x2 + 4x + 3 f(x) = x2 – 4x – 5 f(x) = x2 + 6x + 2 f(x) = –2x2 – 8x + 1 f(x) = –2x2 + 8x – 2

Answer 1

answers:

f(x) = x² + 4x + 3, f(x) = –2x² – 8x + 1,

Answer 2

`f(x) = x^2 + 4x + 3`

`f(x) = -2x^2 - 8x + 1`

Explanation:

`f(x) = x^2 + 4x + 3`

To find axis of symmetry we apply formula

`x= (-b)/(2a)`

a= 1, b= 4

`x= (-4)/(2(1))=-2`

Axis of symmetry at x=-2

`f(x) = x^2 - 4x - 5`

a= 1, b= -4

`x= (4)/(2(1))=2`

Axis of symmetry at x=2

`f(x) = x^2 + 6x + 2`

a= 1, b= 6

`x= (-6)/(2(1))=-3`

Axis of symmetry at x=-3

`f(x) = -2x^2 - 8x + 1`

a= -2, b= -8

`x= (8)/(2(-2))=-2`

Axis of symmetry at x=-2

`f(x) = -2x^2 + 8x - 2`

a= -2, b= 8

`x= (-8)/(2(-2))=2`