Question

F(x) = Square root of quantity x plus nine.; g(x) = 8x - 13

Find f(g(x)).
f(g(x)) = 2Square root of quantity two x minus one.
f(g(x)) = 8Square root of quantity x minus four.
f(g(x)) = 2Square root of quantity two x plus one.
f(g(x)) = 8Square root of quantity x plus nine. - 13

Answer 1

f(x) = sqrt(x) + 9
g(x) = 8x - 13

f(g(x)) = f(8x - 3) = sqrt(8x - 13) + 9

Answer 2

`2√(2x-1)`

Explanation:

f(x) = Square root of quantity x plus nine.

Mathematically we can write this as:

`f(x)=√(x+9)`

`g(x)=8x-13`

We have to find
`f(g(x))`

So, we have to replace x in f(x) with : 8x-13.

`f(g(x))=f(8x-13)`

=
`√(8x-13+9)`

=
`√(8x-4)`

=
`√(4(2x-1))`

=
`2√(2x-1)`

Hence, answer is : f(g(x)) = 2 Square root of quantity two x minus one.