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A soccer ball is kicked with a speed of 8.50 m/s at an angle of 28.0° above the horizontal. if the ball lands at the same level from which it was kicked, how long was it in the air? (neglect air resistance.)

1 Answer

4 votes

Upward velocity at launch= 8.50*sin280

8.50×0.4694

=3.989

Time taken to reach maximum height=v/g

=3.9899/9.8

Same speed to needed to come down,

So, time in air= 3.9899/4.9

=0.81 sec


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