1. Answer;
-825 feet (825 ft)
Step-by-step explanation;
Let the canyon wall be at W feet
The speed of the sound is 750 mph
The distance will be ( 2 ×W) (because the echo is a reflected sound)
The time is 1.5 seconds
Speed = distance /time
but; 1 mile = 5280 ft and 1 hour = 3600 s
Thus; 2W/1.5 = (750 mph)× (5280 ft/1 mile) × (1h / 3600 s)
W = 1100 × 1.5/2
= 825 ft
2. Answer;
= 550n ft
Step-by-step explanation;
Speed = Distance/time
The speed = 750 mph
Time = n seconds
Distance = 2 W
1 mile = 5280 ft , and 1 h = 3600 secs
Therefore; 2W/n = (750 mph) x (5280 ft/ 1 mile) x (1h / 3600 s)
= 2 W/n = 1100
= 2 W = 1100n
W = 550n ft
Thus in terms of n the distance of the canyon from the wall is 550n ft