In the numerator, we can pull a 7 out of the expression 7x + 14 to get the product 7(x + 2). In the denominator, we can factor the expression 2x² + x - 6 like this:
![2x^2+x-6=2x^2+4x-3x-6\\=2x(x+2)-3(x+2)\\=(x+2)(2x-3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ovvutc3u6fk1p481w8f2cfsp9m5g5tpyna.png)
Our fraction can now be written as
![(7(x+2))/((x+2)(2x-3))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/3qkbt4z28nmwa8y0qhwgcnwymffa1rzdcw.png)
the only factor the numerator and denominator share in this case is x + 2.