Question

For the function f (x)=6/2x-3, find the value of each expression below


`f(x) = (6)/(2x - 3)`
a. f (1)
b. f (0)
c. f (-3)
d. f (1.5)
e. what value of x would make f(x)=4 ?

Answer 1

we are given

`f(x) = (6)/(2x - 3)`

(a)

For finding f(1), we can plug x=1 into f(x)

we get

`f(1) = (6)/(2*1 - 3)`

`f(1) = -6`...........Answer

(b)

For finding f(0), we can plug x=0 into f(x)

we get

`f(0) = (6)/(2*0 - 3)`

`f(0) = -2`...........Answer

(c)

For finding f(-3), we can plug x=-3 into f(x)

we get

`f(-3) = (6)/(2*-3 - 3)`

`f(-3) = -(2)/(3)`...........Answer

(d)

For finding f(1.5), we can plug x=1.5 into f(x)

we get

`f(1.5) = (6)/(2*1.5 - 3)`

`f(1.5) =\infty`...........Answer

(e)

We can set f(x)=4

and then we can solve for x

`f(x) = (6)/(2x - 3)=4`

`(6)/(2x-3)\left(2x-3\right)=4\left(2x-3\right)`

`(4\left(2x-3\right))/(4)=(6)/(4)`

`2x-3=(3)/(2)`

`2x=(9)/(2)`

`x=(9)/(4)`...............Answer