Let x represent the first integer
then the second integer is x + 1
and the third integer is x + 2
(x) + (x + 1) + (x + 2) = 393 the sum of the 3 integers is 393
3x + 3 = 393 added like terms
3x = 390 subtracted 3 from both sides
x = 130 divided both sides by 3
since x = 130, then x + 1 = 131, and x + 2 = 132
Answer: 130, 131, 132