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The sides of a triangle are x, x+7, and 2x-8. If the perimeter of the triangle is 47, what is x
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The sides of a triangle are x, x+7, and 2x-8. If the perimeter of the triangle is 47, what is x

User Jonathan Cardoz
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just like the previous one, we sum the sides to get the perimeter.



\bf (x)+(x+7)+(2x-8)=47\implies 4x-1=47\implies 4x=48\\\\\\x=\cfrac{48}{4}\implies x=12

User John Pitts
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