Question

In part 1 of lab 2 you will make and standardize a solution of naoh(aq). suppose in the lab you measure the solid naoh and dissolve it into 100.0 ml of water. you then measure 0.2005 g of khp (kc8h5o4, 204.22 g/mol) and place it in a clean, dry 100-ml beaker, and then dissolve the khp in about 25 ml of water and add a couple of drops of phenolphthalein indicator. you titrate this with your naoh(aq) solution and find that the titration requires 9.82 ml of naoh(aq).

Answer 1

0.100 M

Step-by-step explanation:

KHP is used to standardize the NaOH solution, according to the following neutralization reaction.

KC₈H₅O₄ + NaOH → NaKC₈H₄O₄ + H₂O

We can establish the following relations.

• The molar mass of KHP is 204.22 g/mol.
• The molar ratio of KHP to NaOH is 1:1.

The moles of NaOH that reacted with 0.2005 g of KHP are:

`0.2005gKHP.(1molKHP)/(204.22gKHP) .(1molNaOH)/(1molKHP) =9.818 * 10^(-4) molNaOH`

The molarity of NaOH is:

`M=(9.818 * 10^(-4) mol)/(9.82 * 10^(-3)L) =0.100M`