162k views
3 votes
How many positive integers $n$ satisfy $ floor sqrt n floor = 5$?

User Fabio Mora
by
6.9k points

1 Answer

4 votes

That's all the square roots of the form 5.xxxx. The numbers start at 5² and end at 6²-1.

So that's 6² - 5² = 11 numbers. We can list them:

25,26,27,28,29,30,31,32,33,34,35

Answer: 11


User Acorello
by
6.9k points