Question

How many grams of Fe2O3 are there in 0.500 mole of Fe2O3? 79.8 g ... In this reaction, what is the coefficient for calcium oxide? CaO + CO2

Answer 1

Answer : The mass of
`Fe_2O_3` are, 79.845 grams

In the given reaction, the coefficient for calcium oxide is, 1

Explanation :

Part 1 : Given,

Moles of
`Fe_2O_3` = 0.500 mole

Molar mass of
`Fe_2O_3` = 159.69 g/mole

`\text{Mass of }Fe_2O_3=\text{Moles of }Fe_2O_3* \text{Molar mass of }Fe_2O_3`

`\text{Mass of }Fe_2O_3=0.500mole* 159.69g/mole=79.845g`

Therefore, the mass of
`Fe_2O_3` are, 79.845 grams

Part 2 :

The given balanced chemical reaction will be,

`CaO+CO_2\rightarrow CaCO_3`

This reaction is a balanced reaction in which 1 mole of calcium oxide react with 1 mole of carbon dioxide to give 1 mole of calcium carbonate as a product.

Hence, the coefficient for calcium oxide is, 1

Answer 2

79.8 g; 1

a) Mass of Fe2O3

Molar mass of Fe2O3 = (2x55.845 +3x16.00) g Fe2O3 = 159.69 g Fe2O3

Mass of Fe2O3 = 0.500 mol Fe2O3 x (159.69 g Fe2O3)/1 mol Fe2O3)

= 79.8 g Fe2O3

b) Coefficient of CaO

The balanced equation is

1CaO + CO2 → CaCO3

The coefficient of CaO is 1.