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If xy = 1, what is the value of \small \frac{2^{(x+y)^{2}}}{2^{(x-y)^{2}}}

User Makogan
by
5.3k points

1 Answer

5 votes

Given that xy=1. Now we have to use this equation to find the value of


(2^((x+y)^2))/(2^((x-y)^2))


=2^(\left((x+y)^2-(x-y)^2\right))


=2^(\left(x^2+y^2+2xy-(x^2+y^2-2xy)\right))


=2^(\left(x^2+y^2+2xy-x^2-y^2+2xy\right))


=2^(\left(2xy+2xy\right))


=2^(\left(4xy\right))


=2^(\left(4xy\right))

Now plug the given value of xy=1


=2^(4*1)


=2^(4)


=16

Hence final answer is 16.

User Dmitry Birin
by
5.9k points
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