The distance between the points (6, b0 and (2, -4) is 4 to the sqaure root of five. find the value of b

asked Feb 24, 2019 34.7k views

3 votes

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3 votes

√(6-2)² + (b+4)² = 4√5

√16+b²+8b+16 =√80

b²+8b+32=80

b² + 8b - 48 = 0

(b+12)(b-4)=0

b can be-12 or 4

Chrismear answered Mar 2, 2019

6.4k points

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