Question

What is vertex of x^2+5x-3

Answer 1

`\text{The vertex of}\ ax^2+bx+c:\\\\(h,\ k),\ \text{where}\ h=(-b)/(2a);\ k=f(h)=(-(-b^2-4ac))/(4a)`

`\text{We have:}\\f(x)=x^2+5x-3\\\\a=1,\ b=5,\ c=-3\\\\h=(-5)/(2\cdot1)=(-5)/(2)=-2.5\\\\k=f(-2.5)=(-2.5)^2+5(-2.5)-3=6.25-12.5-3=-9.25`

`\text{Answer: the vertex is in}\ (-2.5;\ -9.25)`