If (5x^4)(2x^6)=ax^b, what is the value of a-b?

asked Sep 4, 2019 78.1k views

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$5x^4\cdot2x^6=ax^b\\10x^(10)=ax^b\\a=10 \wedge b=10$

a-b=10-10=0

Ypakala answered Sep 5, 2019

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$(5x^4)(2x^6)=(5\cdot2)(x^4\cdot x^6)=10x^(4+6)=10x^(10)=ax^b$

$a=10\qquad b=10$

and

$a-b=10-10=\boxed{0}$

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