Let f(x) = x^2 - 16. Find f^-1(x)

asked Jul 25, 2019 12.1k views

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3 votes

$For\ x\geq0$

$f(x)=x^2-16\\\\f^(-1)(x)=?\\\\y=x^2-16\to x=y^2-16\ \ \ \ |+16\\\\x+16=y^2\\\\y^2=x+16\to y=√(x+16)\ for\ x\geq-16$

Asma answered Jul 26, 2019

by Asma

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6 votes

The function is not injective, therefore the inverse doesn't exist.

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