Question

Let f(x) = x^2 - 16. Find f^-1(x)

Answer 1

`For\ x\geq0`

`f(x)=x^2-16\\\\f^(-1)(x)=?\\\\y=x^2-16\to x=y^2-16\ \ \ \ |+16\\\\x+16=y^2\\\\y^2=x+16\to y=√(x+16)\ for\ x\geq-16`

Answer 2

The function is not injective, therefore the inverse doesn't exist.